Mazfix RX8 Turbo Upgrade - Dyno Video
#126
Boosted Kiwi
iTrader: (2)
But people commonly refer to the difference between the two hp numbers as 'drivetrain losses' .
They don't mention anything about rotational losses normally.
So my belief (correct me if I'm wrong) is that the term 'drivetrain losses' refers to the difference between those two numbers.
#127
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
I appreciate the summary and I think I've followed this debate properly but can I just clarify one thing?
When you say "dyno the same" are you only referring to hp or torque as well? That hp won't change is a nail well driven home (and then some
). But if the car accelerates faster, won't the dyno torque numbers improve with a lightened flywheel? Or am I missing something?
When you say "dyno the same" are you only referring to hp or torque as well? That hp won't change is a nail well driven home (and then some
![Uhh](https://www.rx8club.com/images/smilies/uhh.gif)
but Torque is an instentaneous number with no relationship to time. and any given instant in time, the TQ produced would be the same regardless what the flywheel weight. so the plotted curve of points should be the same. the difference is you achieve progression through that curve much faster with less rotational mass
#128
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
if all you care about is an arbitrary number with no detail of usefullness, then sure, call it what you will. see the example of a 700millionHP motor taking 37 days to reach peak power, its "drivetain loss" in that view may only be 40HP(frictional loss)
but thats like trying to measure temperature with a ruler.
in the REAL world, the losses of that 700million HP motor is much more significant than saying "40HP" gives the appearance of.. what good is the power if it takes a month to make it? the race will be over already. and those losses can NOT EVER be defined by Horsepower. It would have to be defined by the rate of change of horsepower made
this is an excellent example of why dyno's are just tools, and basic ones at that. what a dyno can meaure is only a portion of the equation. it can tell you a HP figure to attach with your scales and get a HP/Wt ratio. but a dyno cannot tell you if you make your peak power from idle in 1.4 seconds(as say a high dollar track bike might) or if it takes all day long like an old 3 cyl beat up Geo Metro.
You could make up examples all day long(and better ones) until you had equal total power, identical curves, and equal HP/Wt... but the one that makes te power faster will always win. and it can do that with less rotational weight in the drivetrain, tell me you cant call that less "loss".
Last edited by paulmasoner; 07-25-2010 at 11:42 PM.
#130
Shootin' from the hip
Join Date: Apr 2005
Location: Sydney, Australia
Posts: 7,584
Likes: 0
Received 0 Likes
on
0 Posts
but Torque is an instentaneous number with no relationship to time. and any given instant in time, the TQ produced would be the same regardless what the flywheel weight. so the plotted curve of points should be the same. the difference is you achieve progression through that curve much faster with less rotational mass
So the only way to really measure any benefit from a lightened flywheel is to introduce a time component? Although I suppose it's such an incremental improvement that devising such a test would be difficult - i.e. removing all variables (such as driver response in a drag or a million other things in a lap time).
I guess you could get the same car and time the difference from, say, 40-80km/h, in the same gear before and after installation - that might be a useful real world test. Or am I missing something again?
#131
Boosted Kiwi
iTrader: (2)
Thank you - I understand that.
So the only way to really measure any benefit from a lightened flywheel is to introduce a time component? Although I suppose it's such an incremental improvement that devising such a test would be difficult - i.e. removing all variables (such as driver response in a drag or a million other things in a lap time).
I guess you could get the same car and time the difference from, say, 40-80km/h, in the same gear before and after installation - that might be a useful real world test. Or am I missing something again?
So the only way to really measure any benefit from a lightened flywheel is to introduce a time component? Although I suppose it's such an incremental improvement that devising such a test would be difficult - i.e. removing all variables (such as driver response in a drag or a million other things in a lap time).
I guess you could get the same car and time the difference from, say, 40-80km/h, in the same gear before and after installation - that might be a useful real world test. Or am I missing something again?
#133
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
Thank you - I understand that.
So the only way to really measure any benefit from a lightened flywheel is to introduce a time component? Although I suppose it's such an incremental improvement that devising such a test would be difficult - i.e. removing all variables (such as driver response in a drag or a million other things in a lap time).
I guess you could get the same car and time the difference from, say, 40-80km/h, in the same gear before and after installation - that might be a useful real world test. Or am I missing something again?
So the only way to really measure any benefit from a lightened flywheel is to introduce a time component? Although I suppose it's such an incremental improvement that devising such a test would be difficult - i.e. removing all variables (such as driver response in a drag or a million other things in a lap time).
I guess you could get the same car and time the difference from, say, 40-80km/h, in the same gear before and after installation - that might be a useful real world test. Or am I missing something again?
a proper dyno would not be 2 dimesional. it would be 3 dimensional. HP/TQ, RPM, and time each with their own axis. in that manner you could differentiate actual losses and also not just power, but HOW and WHEN power is delivered in relation to time, which is what all motorsports is based around..
#135
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
the loss(in your rate of change in power output) is directly tied to angular momentum, which does not care if it 300rpms or 3 million. it ONLY cares about CHANGE in RPM
the losses reduced are the same in any gear at any speed at any rpm. you just have to be able to think 3 dimensionally to understand that.
#137
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
if ppl REALLY wanted usefull stuff out of them, they would be 3D just like your tables in your PCM. but thats not what is easy for ppl to understand and wrap their head around, that would destroy armchair racing, and ricer kids wouldnt even know what to brag about anymore
#141
Administrator
way back at the beginning
![Rock](https://www.rx8club.com/images/smilies/rock.gif)
and we will hold you to it- unless you actually strap the engine onto an engine dyno
![Wink](https://www.rx8club.com/images/smilies/wink.gif)
Congratulations! to both of you
![Smilie](https://www.rx8club.com/images/smilies/smile.gif)
oh wait look
I SAID IT FIRST!!
![Big Grin](https://www.rx8club.com/images/smilies/biggrin.gif)
![Beer05](https://www.rx8club.com/images/smilies/beer05.gif)
bold for clarity
#142
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
Here we go again .
I don't need to back it up with math . I understand how this works and have experience with a LWFW so I know I'm correct .
and what your *** dyno told you so?
fixed it for you ....
angular momentum is the correct term. rate of change was a good fix by you
I actually thought you had a clue till you wrote this
I don't need to back it up with math . I understand how this works and have experience with a LWFW so I know I'm correct .
and what your *** dyno told you so?
fixed it for you ....
angular momentum is the correct term. rate of change was a good fix by you
I actually thought you had a clue till you wrote this
#144
Asshole for hire
iTrader: (1)
Join Date: Jun 2006
Location: Colfontaine, Belgium
Posts: 3,214
Likes: 0
Received 3 Likes
on
3 Posts
you're still negating the fact that there are losses that a dyno can not physically measure. percentage, static number, bit of both... none of them are entirely correct. because static power means nothing. for it to be useful it HAS to be related to time. unfortunately that not the world we live in, and i dont think ppl would accept it if it was availible to be done properly.
#149
Administrator
1. in the context of this thread the only thing that mattered was "on a dyno". all of your points(well, mostly) are valid if we we'rent talking about "on the dyno". you and brettus were having 2 different debates. you and I are not
![Wink](https://www.rx8club.com/images/smilies/wink.gif)
2. I purposely didnt go into all of that because, as I said, I love this debate. it's much more fun to watch it unfold then get involved in it. this must be the 8th time i've seen it just on this forum
![Beer05](https://www.rx8club.com/images/smilies/beer05.gif)
#150
Administrator
well i was going to quote you about the dump the clutch post and correct you but then i figured i'd just let it go. besides 42 was wrong.if you had added a rolleyes at the end of your welcome to mazfix the sarcasm would have come across better.nitrogen is too expensive use helium.
oh wait... does this count towards quoting you?
oh wait... does this count towards quoting you?